the L2 norm squares values, so it increases the cost of outliers exponentially
Stability
resistance to horizontal adjustments.
L2 > L1
Computational Difficulty
L2 > L1
L2 has a closed form solution
L1 does not have a closed form solution because it is a non-differenciable piecewise function, as it involves an absolute value. For this reason, L1 is computationally more expensive, as we can’t solve it in terms of matrix math